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SERVOSTAR-620-AS Kollmorgen

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The SERVOSTAR-620-AS is a servo drive from Kollmorgen and is part of the S600 Servo Drives series. It features a peak output current of 40 Arms and a rated output current of 20 Arms, with an installed load capacity of 14 kVA. The drive operates with an auxiliary supply voltage of 24 VDC and weighs 7.5 kilograms.

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Product Description:

The SERVOSTAR-620-AS is a digital servo drive produced by Kollmorgen within the S600 Servo Drives series. The unit serves as the power conversion and control stage between facility AC mains and a permanent-magnet servo motor, supplying regulated current loops for precise industrial motion across indexing, feed, and positioning axes. By integrating velocity and torque algorithms in its embedded processor, the drive enables coordinated axis control in packaging, material-handling, and machine-tool installations that demand fast response and repeatable positioning.

In operation, the drive draws control logic power from an auxiliary bus of 24 VDC, while the power section can continuously deliver 20 Arms to the load and tolerate momentary bursts up to 40 Arms during acceleration. A high-speed current loop that closes every 62.5 µs keeps torque ripple low, a figure supported by the current form factor of 1.01, which indicates near-sinusoidal output. The built-in brake chopper is matched to an internal resistor of 33 Ω, allowing kinetic energy from vertical axes to be dissipated without an external dump module. The supply network must be sized for an installed load of 14 kVA; within this range, the drive accepts motor windings from 2 mH to 12 mH, so both low-inductance and high-inductance servomotors remain stable. A residual voltage drop of 5 V across the output stage helps estimate cable losses, and the quiescent dissipation of 15 W minimizes cabinet heating when the machine is idle.

During continuous operation, the drive releases 200 W of heat that must be removed by cabinet airflow or external heat sinks. The housing measures 120 mm in width, 265 mm in depth, and 275 mm in height, enabling dense multi-axis layouts without exceeding standard enclosure depths. With a mass of 7.5 kg, the drive provides the rigidity needed for vibration-prone installations.

Aux Supply Voltage
24 VDC
Current Form Factor
1.01
Current Loop Cycle
62.5 µs
Depth
265 mm
Height
275 mm
Installed Load
14 kVA
Internal Brake Resistor
33 Ω
Max Load Inductance
12 mH
Min Load Inductance
2 mH
Peak Output Current
40 Arms
Quiescent Dissipation
15 W
Rated Dissipation
200 W
Rated Output Current
20 Arms
Residual Voltage Drop
5 V
Weight
7.5 kg
Width
120 mm
Instructions

Use this calculator to convert between different units of mass. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Mass

Mass is a fundamental property of objects that measures the amount of matter contained within. It is distinct from weight, which depends on both mass and the gravitational force acting on it. The International System of Units (SI) uses the kilogram (kg) as the standard unit of mass. Familiarity with mass and its units is crucial in various fields, including physics, engineering, and industrial automation.

Importance for Industrial Automation and Servomotors

In industrial automation, precise control of mass and weight is paramount. For instance, servomotors, which are integral components in automation, rely on accurate mass calculations to optimize performance and efficiency. These motors use feedback systems to ensure precise movement, which requires accounting for the mass of mechanical parts and loads. By effectively managing mass, automation systems can achieve higher precision and reliability, minimizing energy consumption and wear on components.

Understanding and converting mass units can enhance the adaptability of automation systems in a global market, where different countries and industries may use diverse measurement units. Thus, a mass conversion tool serves as a practical resource for engineers and technicians, facilitating seamless integration and operation across different scales and measurement standards.

Instructions

Use this calculator to convert between different units of mass. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Mass

Mass is a fundamental property of objects that measures the amount of matter contained within. It is distinct from weight, which depends on both mass and the gravitational force acting on it. The International System of Units (SI) uses the kilogram (kg) as the standard unit of mass. Familiarity with mass and its units is crucial in various fields, including physics, engineering, and industrial automation.

Importance for Industrial Automation and Servomotors

In industrial automation, precise control of mass and weight is paramount. For instance, servomotors, which are integral components in automation, rely on accurate mass calculations to optimize performance and efficiency. These motors use feedback systems to ensure precise movement, which requires accounting for the mass of mechanical parts and loads. By effectively managing mass, automation systems can achieve higher precision and reliability, minimizing energy consumption and wear on components.

Understanding and converting mass units can enhance the adaptability of automation systems in a global market, where different countries and industries may use diverse measurement units. Thus, a mass conversion tool serves as a practical resource for engineers and technicians, facilitating seamless integration and operation across different scales and measurement standards.

Instructions

How to Determine What Torque You Need for Your Servo Motors

When building a robotic system with servo motors, determining the appropriate torque for each motor is essential. Torque is what allows the servo motor to effectively lift, hold, or move an object. Without sufficient torque, your motor either won’t perform as expected or may damage itself trying.

Here, we’ll break down how to calculate the torque you need, then pivot into some key nuances around how torque works in different contexts.

What Is Torque?

Illustration of torque around a central axis

Torque is a force applied over a distance that causes rotation. You use torque every day when you twist open a jar or turn a doorknob. In the case of servo motors—specifically in robotics—torque determines how much weight a motor can rotate at a certain distance away from its axis. Think about a robotic arm lifting a heavy object: the motor's torque directly affects how much weight the arm can lift, and at what speed.

Mathematically, torque is expressed as:

τ = r × F

  • τ is torque,
  • r is the distance from the axis of rotation,
  • F is the force applied.

If that feels abstract, consider that F is usually the force caused by gravity, meaning it depends on the weight of the object and its distance from the motor's center.

Torque and Servo Motors: The Core Relationship

Illustration of a load at the end of a lever demonstrating it

Servo motors are frequently used in robotic arms or other machines with rotational mechanisms. The amount of torque a servo motor can exert determines its capability to perform mechanical tasks, especially when dealing with varying loads.

The lever arm length—the distance from the rotation point to the load—amplifies the effect of the weight being moved. A longer lever arm requires more torque even if the weight remains the same. So, as we dive into calculations, remember that torque isn't just about force; it’s also about how far away from the motor's axis that force is applied.

Formula Recap

The standard torque equation for servo motors typically used in applications like robotic arms can be expanded slightly:

τ = r × m × g

  • r is the distance from the motor's axis to where the load is applied,
  • m is the mass of the item being moved (in kilograms),
  • g is the acceleration of gravity (~9.81 m/s²).

Let’s translate this into something more immediately practical: a robotic arm needs torque to lift an object at the end of the arm. If the arm is long, you’ll need more torque to achieve that same lift, even if the object you’re lifting doesn’t change in weight.

Components of Torque in Servo Motors

1. Weight of Components

The force caused by the weight of objects being moved is simple physics. Every load you expect the motor to handle has a weight. Multiplied by gravity, that’s your F.

A robotic arm lifting a box must overcome the weight of the box. However, the motor also needs to account for the weight of the components themselves, like robotic arm links or grippers.

2. Distance from the Pivot

The lever arm length is just as crucial. Calculating torque by only considering force and weight without factoring in the arm’s length will result in inaccurate torque requirements and potentially a poor design.

Case Study: A Simple Robotic Arm

Imagine an arm that needs to lift a 1.5 kg box at the end of a 0.5-meter-long arm.

  • m = 1.5 kg
  • r = 0.5 m
  • g = 9.81 m/s² (constant)

We’re now ready to plug in values:

τ = r × m × g

τ = 0.5 m × 1.5 kg × 9.81 m/s²

τ = 7.36 Nm

This means you require a minimum torque of 7.36 Newton-meters (Nm) to lift the box at the end of this particular robotic arm.

Angular Acceleration

In any instance where you need the servo motor to move a load and not just hold it, you must also account for angular acceleration. Angular acceleration means your motor needs extra torque at the beginning and during changes in movement. To calculate it:

τ = I × α

  • I is the moment of inertia of the robot arm (resistance to angular motion),
  • α is angular acceleration.

This means that for movements such as high-speed rotations or rapid direction changes, torque requirements jump. The speed with which the load moves and how quickly the direction changes are factored into torque calculations for dynamic motion.

Final Thoughts

To summarize everything, calculating torque isn’t just as simple as deciding how heavy a load is. It requires you to think about:

  • Distance (where the weight is applied from the axis),
  • Weight of the object being moved,
  • The weight of other mechanical components (like links and joints inside the machine),
  • Angular acceleration, especially if the motor will be moving or changing directions rapidly,
  • Safety margins (plan a buffer of 20-30% torque capability beyond the minimum).

The general idea is that the larger the load or the further away from the pivot, the more torque you need. By thinking through all of these details, you can properly size your servo motor torque needs, ensuring your motor will handle everything smoothly without underperformance during operation.

Get expert servo motor guidance and competitive pricing from Wake Industrial. Whether you need one motor or a complete system, we'll help you find the right solution at the right price. Call 1-919-443-0207 now for a quick quote or email sales@wakeindustrial.com to browse our extensive servo motor inventory.

Instructions

How to Determine What Torque You Need for Your Servo Motors

When building a robotic system with servo motors, determining the appropriate torque for each motor is essential. Torque is what allows the servo motor to effectively lift, hold, or move an object. Without sufficient torque, your motor either won’t perform as expected or may damage itself trying.

Here, we’ll break down how to calculate the torque you need, then pivot into some key nuances around how torque works in different contexts.

What Is Torque?

Illustration of torque around a central axis

Torque is a force applied over a distance that causes rotation. You use torque every day when you twist open a jar or turn a doorknob. In the case of servo motors—specifically in robotics—torque determines how much weight a motor can rotate at a certain distance away from its axis. Think about a robotic arm lifting a heavy object: the motor's torque directly affects how much weight the arm can lift, and at what speed.

Mathematically, torque is expressed as:

τ = r × F

  • τ is torque,
  • r is the distance from the axis of rotation,
  • F is the force applied.

If that feels abstract, consider that F is usually the force caused by gravity, meaning it depends on the weight of the object and its distance from the motor's center.

Torque and Servo Motors: The Core Relationship

Illustration of a load at the end of a lever demonstrating it

Servo motors are frequently used in robotic arms or other machines with rotational mechanisms. The amount of torque a servo motor can exert determines its capability to perform mechanical tasks, especially when dealing with varying loads.

The lever arm length—the distance from the rotation point to the load—amplifies the effect of the weight being moved. A longer lever arm requires more torque even if the weight remains the same. So, as we dive into calculations, remember that torque isn't just about force; it’s also about how far away from the motor's axis that force is applied.

Formula Recap

The standard torque equation for servo motors typically used in applications like robotic arms can be expanded slightly:

τ = r × m × g

  • r is the distance from the motor's axis to where the load is applied,
  • m is the mass of the item being moved (in kilograms),
  • g is the acceleration of gravity (~9.81 m/s²).

Let’s translate this into something more immediately practical: a robotic arm needs torque to lift an object at the end of the arm. If the arm is long, you’ll need more torque to achieve that same lift, even if the object you’re lifting doesn’t change in weight.

Components of Torque in Servo Motors

1. Weight of Components

The force caused by the weight of objects being moved is simple physics. Every load you expect the motor to handle has a weight. Multiplied by gravity, that’s your F.

A robotic arm lifting a box must overcome the weight of the box. However, the motor also needs to account for the weight of the components themselves, like robotic arm links or grippers.

2. Distance from the Pivot

The lever arm length is just as crucial. Calculating torque by only considering force and weight without factoring in the arm’s length will result in inaccurate torque requirements and potentially a poor design.

Case Study: A Simple Robotic Arm

Imagine an arm that needs to lift a 1.5 kg box at the end of a 0.5-meter-long arm.

  • m = 1.5 kg
  • r = 0.5 m
  • g = 9.81 m/s² (constant)

We’re now ready to plug in values:

τ = r × m × g

τ = 0.5 m × 1.5 kg × 9.81 m/s²

τ = 7.36 Nm

This means you require a minimum torque of 7.36 Newton-meters (Nm) to lift the box at the end of this particular robotic arm.

Angular Acceleration

In any instance where you need the servo motor to move a load and not just hold it, you must also account for angular acceleration. Angular acceleration means your motor needs extra torque at the beginning and during changes in movement. To calculate it:

τ = I × α

  • I is the moment of inertia of the robot arm (resistance to angular motion),
  • α is angular acceleration.

This means that for movements such as high-speed rotations or rapid direction changes, torque requirements jump. The speed with which the load moves and how quickly the direction changes are factored into torque calculations for dynamic motion.

Final Thoughts

To summarize everything, calculating torque isn’t just as simple as deciding how heavy a load is. It requires you to think about:

  • Distance (where the weight is applied from the axis),
  • Weight of the object being moved,
  • The weight of other mechanical components (like links and joints inside the machine),
  • Angular acceleration, especially if the motor will be moving or changing directions rapidly,
  • Safety margins (plan a buffer of 20-30% torque capability beyond the minimum).

The general idea is that the larger the load or the further away from the pivot, the more torque you need. By thinking through all of these details, you can properly size your servo motor torque needs, ensuring your motor will handle everything smoothly without underperformance during operation.

Get expert servo motor guidance and competitive pricing from Wake Industrial. Whether you need one motor or a complete system, we'll help you find the right solution at the right price. Call 1-919-443-0207 now for a quick quote or email sales@wakeindustrial.com to browse our extensive servo motor inventory.

Instructions

Use this calculator to convert between different units of power. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Power Units

Power is a foundational concept in both everyday life and industrial applications. The term "watts" is ubiquitous, named after James Watt, a pivotal figure in the industrial revolution known for his advancements in steam engine technology. A watt represents the rate at which energy is transferred or converted and forms the basis for other power units such as kilowatts (1,000 watts), megawatts (1,000,000 watts), and more.

Importance in Industrial Automation and Servomotors

In industrial automation, precise power control is critical for maximizing efficiency and accuracy. Servomotors, essential components in automation systems, rely heavily on accurate power measurement. These motors, often used in robotics and CNC machinery, require specific power inputs to function correctly, translating electrical energy into controlled movements. The ability to convert between different power units helps engineers and technicians optimize these systems for energy consumption and performance. Whether ensuring that a robotic arm operates with sufficient power or managing the electrical requirements of a complex assembly line, understanding and converting power units is a crucial skill.

As technology advances, the necessity for precision grows. Power conversion tools, therefore, play an indispensable role in maintaining system efficiency and reliability, making them a staple in the toolkit of modern engineers and industrial technicians.

Instructions

Use this calculator to convert between different units of power. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Power Units

Power is a foundational concept in both everyday life and industrial applications. The term "watts" is ubiquitous, named after James Watt, a pivotal figure in the industrial revolution known for his advancements in steam engine technology. A watt represents the rate at which energy is transferred or converted and forms the basis for other power units such as kilowatts (1,000 watts), megawatts (1,000,000 watts), and more.

Importance in Industrial Automation and Servomotors

In industrial automation, precise power control is critical for maximizing efficiency and accuracy. Servomotors, essential components in automation systems, rely heavily on accurate power measurement. These motors, often used in robotics and CNC machinery, require specific power inputs to function correctly, translating electrical energy into controlled movements. The ability to convert between different power units helps engineers and technicians optimize these systems for energy consumption and performance. Whether ensuring that a robotic arm operates with sufficient power or managing the electrical requirements of a complex assembly line, understanding and converting power units is a crucial skill.

As technology advances, the necessity for precision grows. Power conversion tools, therefore, play an indispensable role in maintaining system efficiency and reliability, making them a staple in the toolkit of modern engineers and industrial technicians.

Frequently Asked Questions about SERVOSTAR-620-AS:

Q: What is the rated output current for the SERVOSTAR-620-AS servo drive?

A: The SERVOSTAR-620-AS has a rated output current of 20 Arms, making it suitable for mid-to-high power servo applications.

Q: What is the peak output current capability of the SERVOSTAR-620-AS?

A: This servo drive supports a peak output current of 40 Arms, allowing for short-duration current surges during demanding motion cycles.

Q: What is the resistance value of the internal brake resistor in the SERVOSTAR-620-AS?

A: The internal brake resistor on the SERVOSTAR-620-AS is rated at 33 Ω to safely dissipate braking energy.

Q: What auxiliary supply voltage does the SERVOSTAR-620-AS require?

A: The auxiliary supply voltage required for operation is 24 VDC.

Q: What is the installed load rating for the SERVOSTAR-620-AS?

A: This model has an installed load capacity of 14 kVA, supporting demanding motor loads.


Internal Product Review

  • ‘‘The SERVOSTAR-620-AS is a Kollmorgen servo drive with 20 Arms rated output current and 40 Arms peak output current. A 62.5 µs current loop cycle and 1.01 current form factor give the drive impressive control stability and responsive performance. The 14 kVA installed load and 33 Ω internal brake resistor make the unit a strong choice for demanding motion applications.’’

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