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SERVOSTAR-343 Kollmorgen

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The SERVOSTAR-343 is a servo drive made by Kollmorgen as part of the S300 Servo Drives series. It features a rated input power of 2.5 kVA and a peak output current of 7.5 Arms. The drive has an internal brake resistor of 91 Ohms and a maximum DC bus voltage of 900 VDC.

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Product Description:

The SERVOSTAR-343 is a digital servo amplifier developed by Kollmorgen for the S300 Servo Drives series. It converts a three-phase supply into a controlled DC bus and pulse-width-modulated output that regulates synchronous or induction motors in automated packaging, material-handling, and positioning equipment. By combining current, voltage, and thermal monitoring with integrated braking circuitry, the unit provides the torque commands and speed control required by a motion controller while fitting into compact machine cabinets.

The DC-link circuitry is rated for up to 900 VDC, while an overvoltage trip disconnects the drive if the bus reaches 800 VDC when operating from a 400 V supply. The brake switch engages at 720 VDC to protect the semiconductors. The IGBT output bridge switches at 8 kHz, and the control system increases the carrier frequency to 16 kHz when load current falls to half of the rated value to reduce audible noise. Continuous torque delivery is supported by a rated phase current of 4 A RMS, while momentary acceleration can draw up to 7.5 A RMS. A line demand of 2.5 kVA helps determine the required cabinet feeder capacity. The DC-link conductor pair has a residual voltage drop of only 5 V, supporting responsive power delivery during dynamic operation. Voltage edges rise at 5.7 kV/µs, so the motor cable insulation must be suitable for this rate of voltage change.

The internal regeneration network absorbs mechanical energy with 50 W of continuous braking power through a 91 Ω resistor, allowing most indexing cycles to operate without an external braking resistor. Motor compatibility requires a minimum inductance of 8.9 mH at 400 V, while motors with lower inductance require series reactors. Heat loss is 12 W when the output stage is disabled and increases to 60 W at rated load, so the cabinet must provide adequate ventilation around the amplifier. Airborne sound remains below 45 dB(A) at a distance of one meter, limiting audible noise near the installed drive.

Brake Switch-on Threshold At 400 V
720 VDC
Internal Brake Power
50 W
Internal Brake Resistor
91 Ω
Max Dc Bus Voltage
900 VDC
Max Noise Emission
45 dB(A)
Minimum Motor Inductance At 400 V
8.9 mH
Output Stage Frequency
8 kHz
Overvoltage Trip At 400 V
800 VDC
Peak Output Current
7.5 Arms
Rated Input Power
2.5 kVA
Rated Output Current At 400 V
4 Arms
Residual Voltage Drop
5 V
Switching Frequency At 50% Current
16 kHz
Thermal Dissipation Disabled
12 W
Thermal Dissipation Rated Load
60 W
Voltage Rise Speed At 400 V
5.7 kV/µs

Frequently Asked Questions about SERVOSTAR-343:

Q: What is the rated output current of the SERVOSTAR-343 at 400 V?

A: The SERVOSTAR-343 has a rated output current of 4 Arms at 400 V, supporting medium power servo applications.

Q: What is the value of the internal brake resistor in the SERVOSTAR-343?

A: This drive features an internal brake resistor rated at 91 Ω, suitable for managing braking energy during deceleration.

Q: What is the peak output current the SERVOSTAR-343 can supply?

A: The SERVOSTAR-343 drive has a peak output current capability of 7.5 Arms.

Q: What is the rated input power for the SERVOSTAR-343 drive?

A: With a rated input power of 2.5 kVA, the SERVOSTAR-343 is designed to operate effectively in demanding automation tasks.

Q: What is the maximum noise emission level for the SERVOSTAR-343?

A: Noise emission from the SERVOSTAR-343 reaches a maximum of 45 dB(A), enabling operation in noise-sensitive environments.

Instructions

Use this calculator to convert between different units of mass. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Mass

Mass is a fundamental property of objects that measures the amount of matter contained within. It is distinct from weight, which depends on both mass and the gravitational force acting on it. The International System of Units (SI) uses the kilogram (kg) as the standard unit of mass. Familiarity with mass and its units is crucial in various fields, including physics, engineering, and industrial automation.

Importance for Industrial Automation and Servomotors

In industrial automation, precise control of mass and weight is paramount. For instance, servomotors, which are integral components in automation, rely on accurate mass calculations to optimize performance and efficiency. These motors use feedback systems to ensure precise movement, which requires accounting for the mass of mechanical parts and loads. By effectively managing mass, automation systems can achieve higher precision and reliability, minimizing energy consumption and wear on components.

Understanding and converting mass units can enhance the adaptability of automation systems in a global market, where different countries and industries may use diverse measurement units. Thus, a mass conversion tool serves as a practical resource for engineers and technicians, facilitating seamless integration and operation across different scales and measurement standards.

Instructions

Use this calculator to convert between different units of mass. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Mass

Mass is a fundamental property of objects that measures the amount of matter contained within. It is distinct from weight, which depends on both mass and the gravitational force acting on it. The International System of Units (SI) uses the kilogram (kg) as the standard unit of mass. Familiarity with mass and its units is crucial in various fields, including physics, engineering, and industrial automation.

Importance for Industrial Automation and Servomotors

In industrial automation, precise control of mass and weight is paramount. For instance, servomotors, which are integral components in automation, rely on accurate mass calculations to optimize performance and efficiency. These motors use feedback systems to ensure precise movement, which requires accounting for the mass of mechanical parts and loads. By effectively managing mass, automation systems can achieve higher precision and reliability, minimizing energy consumption and wear on components.

Understanding and converting mass units can enhance the adaptability of automation systems in a global market, where different countries and industries may use diverse measurement units. Thus, a mass conversion tool serves as a practical resource for engineers and technicians, facilitating seamless integration and operation across different scales and measurement standards.

Instructions

How to Determine What Torque You Need for Your Servo Motors

When building a robotic system with servo motors, determining the appropriate torque for each motor is essential. Torque is what allows the servo motor to effectively lift, hold, or move an object. Without sufficient torque, your motor either won’t perform as expected or may damage itself trying.

Here, we’ll break down how to calculate the torque you need, then pivot into some key nuances around how torque works in different contexts.

What Is Torque?

Illustration of torque around a central axis

Torque is a force applied over a distance that causes rotation. You use torque every day when you twist open a jar or turn a doorknob. In the case of servo motors—specifically in robotics—torque determines how much weight a motor can rotate at a certain distance away from its axis. Think about a robotic arm lifting a heavy object: the motor's torque directly affects how much weight the arm can lift, and at what speed.

Mathematically, torque is expressed as:

τ = r × F

  • τ is torque,
  • r is the distance from the axis of rotation,
  • F is the force applied.

If that feels abstract, consider that F is usually the force caused by gravity, meaning it depends on the weight of the object and its distance from the motor's center.

Torque and Servo Motors: The Core Relationship

Illustration of a load at the end of a lever demonstrating it

Servo motors are frequently used in robotic arms or other machines with rotational mechanisms. The amount of torque a servo motor can exert determines its capability to perform mechanical tasks, especially when dealing with varying loads.

The lever arm length—the distance from the rotation point to the load—amplifies the effect of the weight being moved. A longer lever arm requires more torque even if the weight remains the same. So, as we dive into calculations, remember that torque isn't just about force; it’s also about how far away from the motor's axis that force is applied.

Formula Recap

The standard torque equation for servo motors typically used in applications like robotic arms can be expanded slightly:

τ = r × m × g

  • r is the distance from the motor's axis to where the load is applied,
  • m is the mass of the item being moved (in kilograms),
  • g is the acceleration of gravity (~9.81 m/s²).

Let’s translate this into something more immediately practical: a robotic arm needs torque to lift an object at the end of the arm. If the arm is long, you’ll need more torque to achieve that same lift, even if the object you’re lifting doesn’t change in weight.

Components of Torque in Servo Motors

1. Weight of Components

The force caused by the weight of objects being moved is simple physics. Every load you expect the motor to handle has a weight. Multiplied by gravity, that’s your F.

A robotic arm lifting a box must overcome the weight of the box. However, the motor also needs to account for the weight of the components themselves, like robotic arm links or grippers.

2. Distance from the Pivot

The lever arm length is just as crucial. Calculating torque by only considering force and weight without factoring in the arm’s length will result in inaccurate torque requirements and potentially a poor design.

Case Study: A Simple Robotic Arm

Imagine an arm that needs to lift a 1.5 kg box at the end of a 0.5-meter-long arm.

  • m = 1.5 kg
  • r = 0.5 m
  • g = 9.81 m/s² (constant)

We’re now ready to plug in values:

τ = r × m × g

τ = 0.5 m × 1.5 kg × 9.81 m/s²

τ = 7.36 Nm

This means you require a minimum torque of 7.36 Newton-meters (Nm) to lift the box at the end of this particular robotic arm.

Angular Acceleration

In any instance where you need the servo motor to move a load and not just hold it, you must also account for angular acceleration. Angular acceleration means your motor needs extra torque at the beginning and during changes in movement. To calculate it:

τ = I × α

  • I is the moment of inertia of the robot arm (resistance to angular motion),
  • α is angular acceleration.

This means that for movements such as high-speed rotations or rapid direction changes, torque requirements jump. The speed with which the load moves and how quickly the direction changes are factored into torque calculations for dynamic motion.

Final Thoughts

To summarize everything, calculating torque isn’t just as simple as deciding how heavy a load is. It requires you to think about:

  • Distance (where the weight is applied from the axis),
  • Weight of the object being moved,
  • The weight of other mechanical components (like links and joints inside the machine),
  • Angular acceleration, especially if the motor will be moving or changing directions rapidly,
  • Safety margins (plan a buffer of 20-30% torque capability beyond the minimum).

The general idea is that the larger the load or the further away from the pivot, the more torque you need. By thinking through all of these details, you can properly size your servo motor torque needs, ensuring your motor will handle everything smoothly without underperformance during operation.

Get expert servo motor guidance and competitive pricing from Wake Industrial. Whether you need one motor or a complete system, we'll help you find the right solution at the right price. Call 1-919-443-0207 now for a quick quote or email sales@wakeindustrial.com to browse our extensive servo motor inventory.

Instructions

How to Determine What Torque You Need for Your Servo Motors

When building a robotic system with servo motors, determining the appropriate torque for each motor is essential. Torque is what allows the servo motor to effectively lift, hold, or move an object. Without sufficient torque, your motor either won’t perform as expected or may damage itself trying.

Here, we’ll break down how to calculate the torque you need, then pivot into some key nuances around how torque works in different contexts.

What Is Torque?

Illustration of torque around a central axis

Torque is a force applied over a distance that causes rotation. You use torque every day when you twist open a jar or turn a doorknob. In the case of servo motors—specifically in robotics—torque determines how much weight a motor can rotate at a certain distance away from its axis. Think about a robotic arm lifting a heavy object: the motor's torque directly affects how much weight the arm can lift, and at what speed.

Mathematically, torque is expressed as:

τ = r × F

  • τ is torque,
  • r is the distance from the axis of rotation,
  • F is the force applied.

If that feels abstract, consider that F is usually the force caused by gravity, meaning it depends on the weight of the object and its distance from the motor's center.

Torque and Servo Motors: The Core Relationship

Illustration of a load at the end of a lever demonstrating it

Servo motors are frequently used in robotic arms or other machines with rotational mechanisms. The amount of torque a servo motor can exert determines its capability to perform mechanical tasks, especially when dealing with varying loads.

The lever arm length—the distance from the rotation point to the load—amplifies the effect of the weight being moved. A longer lever arm requires more torque even if the weight remains the same. So, as we dive into calculations, remember that torque isn't just about force; it’s also about how far away from the motor's axis that force is applied.

Formula Recap

The standard torque equation for servo motors typically used in applications like robotic arms can be expanded slightly:

τ = r × m × g

  • r is the distance from the motor's axis to where the load is applied,
  • m is the mass of the item being moved (in kilograms),
  • g is the acceleration of gravity (~9.81 m/s²).

Let’s translate this into something more immediately practical: a robotic arm needs torque to lift an object at the end of the arm. If the arm is long, you’ll need more torque to achieve that same lift, even if the object you’re lifting doesn’t change in weight.

Components of Torque in Servo Motors

1. Weight of Components

The force caused by the weight of objects being moved is simple physics. Every load you expect the motor to handle has a weight. Multiplied by gravity, that’s your F.

A robotic arm lifting a box must overcome the weight of the box. However, the motor also needs to account for the weight of the components themselves, like robotic arm links or grippers.

2. Distance from the Pivot

The lever arm length is just as crucial. Calculating torque by only considering force and weight without factoring in the arm’s length will result in inaccurate torque requirements and potentially a poor design.

Case Study: A Simple Robotic Arm

Imagine an arm that needs to lift a 1.5 kg box at the end of a 0.5-meter-long arm.

  • m = 1.5 kg
  • r = 0.5 m
  • g = 9.81 m/s² (constant)

We’re now ready to plug in values:

τ = r × m × g

τ = 0.5 m × 1.5 kg × 9.81 m/s²

τ = 7.36 Nm

This means you require a minimum torque of 7.36 Newton-meters (Nm) to lift the box at the end of this particular robotic arm.

Angular Acceleration

In any instance where you need the servo motor to move a load and not just hold it, you must also account for angular acceleration. Angular acceleration means your motor needs extra torque at the beginning and during changes in movement. To calculate it:

τ = I × α

  • I is the moment of inertia of the robot arm (resistance to angular motion),
  • α is angular acceleration.

This means that for movements such as high-speed rotations or rapid direction changes, torque requirements jump. The speed with which the load moves and how quickly the direction changes are factored into torque calculations for dynamic motion.

Final Thoughts

To summarize everything, calculating torque isn’t just as simple as deciding how heavy a load is. It requires you to think about:

  • Distance (where the weight is applied from the axis),
  • Weight of the object being moved,
  • The weight of other mechanical components (like links and joints inside the machine),
  • Angular acceleration, especially if the motor will be moving or changing directions rapidly,
  • Safety margins (plan a buffer of 20-30% torque capability beyond the minimum).

The general idea is that the larger the load or the further away from the pivot, the more torque you need. By thinking through all of these details, you can properly size your servo motor torque needs, ensuring your motor will handle everything smoothly without underperformance during operation.

Get expert servo motor guidance and competitive pricing from Wake Industrial. Whether you need one motor or a complete system, we'll help you find the right solution at the right price. Call 1-919-443-0207 now for a quick quote or email sales@wakeindustrial.com to browse our extensive servo motor inventory.

Instructions

Use this calculator to convert between different units of power. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Power Units

Power is a foundational concept in both everyday life and industrial applications. The term "watts" is ubiquitous, named after James Watt, a pivotal figure in the industrial revolution known for his advancements in steam engine technology. A watt represents the rate at which energy is transferred or converted and forms the basis for other power units such as kilowatts (1,000 watts), megawatts (1,000,000 watts), and more.

Importance in Industrial Automation and Servomotors

In industrial automation, precise power control is critical for maximizing efficiency and accuracy. Servomotors, essential components in automation systems, rely heavily on accurate power measurement. These motors, often used in robotics and CNC machinery, require specific power inputs to function correctly, translating electrical energy into controlled movements. The ability to convert between different power units helps engineers and technicians optimize these systems for energy consumption and performance. Whether ensuring that a robotic arm operates with sufficient power or managing the electrical requirements of a complex assembly line, understanding and converting power units is a crucial skill.

As technology advances, the necessity for precision grows. Power conversion tools, therefore, play an indispensable role in maintaining system efficiency and reliability, making them a staple in the toolkit of modern engineers and industrial technicians.

Instructions

Use this calculator to convert between different units of power. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Power Units

Power is a foundational concept in both everyday life and industrial applications. The term "watts" is ubiquitous, named after James Watt, a pivotal figure in the industrial revolution known for his advancements in steam engine technology. A watt represents the rate at which energy is transferred or converted and forms the basis for other power units such as kilowatts (1,000 watts), megawatts (1,000,000 watts), and more.

Importance in Industrial Automation and Servomotors

In industrial automation, precise power control is critical for maximizing efficiency and accuracy. Servomotors, essential components in automation systems, rely heavily on accurate power measurement. These motors, often used in robotics and CNC machinery, require specific power inputs to function correctly, translating electrical energy into controlled movements. The ability to convert between different power units helps engineers and technicians optimize these systems for energy consumption and performance. Whether ensuring that a robotic arm operates with sufficient power or managing the electrical requirements of a complex assembly line, understanding and converting power units is a crucial skill.

As technology advances, the necessity for precision grows. Power conversion tools, therefore, play an indispensable role in maintaining system efficiency and reliability, making them a staple in the toolkit of modern engineers and industrial technicians.


Internal Product Review

  • ‘‘The SERVOSTAR-343 is a Kollmorgen S300 servo drive with 2.5 kVA rated input power and 4 Arms rated output current at 400 V. An 8 kHz output stage frequency and 7.5 Arms peak output current support crisp response and stable motor control in demanding motion applications. Low 45 dB(A) noise emission rounds out a highly capable servo drive.’’

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