SERVOSTAR-343

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The SERVOSTAR-343 is a high-performance servo drive with a rated input power of 2.5 kVA and a rated supply voltage range of 3 × 208V to 480V at 50/60 Hz. Manufactured by Kollmorgen and part of the S300 Servo Drives series, it weighs approximately 2.7 kg. It features a current controller bandwidth of over 1.2 kHz.

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Product Description:

Kollmorgen top-rated S300 Servo Drives series has one of the best modules SERVOSTAR-343. It operates on rated supply voltage of 3 x 208V (-10%) to 480V (+10%), 50 / 60 Hz and it also guarantees reliable integration into various industrial power networks. During S1 operation, it operates at rated input power of 2.5 kVA. This servo module has a maximum DC bus voltage of 0.9 kV, which offers relatively high voltage margin for efficient power conversion. Using at 3x208V/3x230V, the device will deliver a rated output current of 5 Arms rms ±3%, and 4 Arms at 3x400V and 3 Arms at 3x480V.

The unit also offers the maximum motor compatibility from an available current output adaptable to the motor. For about 5 seconds, it reaches a peak output current of 7.5 A. The transient load requirements are met by this surge capacity during start up and then output stage switches at 8 kHz, increasing to 16 kHz at 50 % load. 800 VDC is set as the overvoltage switch off threshold. At 3x208V the minimum motor inductance equals 4.6 mH and at 3x230V it is 5.1 mH; these values are low enough to operate with motors of smaller induction. The form factor of the output current is 1.01. The bandwidth of the current controller is exceeded 1.2 kHz. These compact dimensions facilitate efficient space utilization.

The model SERVOSTAR-343 achieves a 95% efficiency rating. A built-in diagnostic LED display provides real-time error codes as this feature simplifies troubleshooting and maintenance. The residual voltage drop at rated current is 5 V. The thermal dissipation at rated current is approximately 60 W, including PSU losses yet excluding regeneration dissipation. The drive weighs around 2.7 kg which eases installation and handling. Its height is about 278 mm and measures 70 mm in width and 171 mm in depth without connectors.

Current Controller Bandwidth
>1.2 kHz
Form Factor Of Output Current
1.01
Height (without Connectors)
Approximately 278 mm
Maximum Dc Bus Voltage
900 V
Motor Inductance Minimum
4.6 mH at 3x208V; 5.1 mH at 3x230V (values for type 343)
Overvoltage Switch-off Threshold
800 VDC
Peak Output Current (approx. 5 S, ±3%)
7.5 Arms (across all supply variants)
Rated Input Power (s1 Operation)
2.5 kVA
Rated Output Current (rms, ±3%)
5 Arms at 3x208V/3x230V; 4 Arms at 3x400V; 3 Arms at 3x480V
Rated Supply Voltage
3 x 208V (-10%) to 480V (+10%), 50/60 Hz
Residual Voltage Drop At Rated Current
5 V
Switching Frequency Of Output Stage
8 kHz (16 kHz when operating at 50% load)
Thermal Dissipation At Rated Current
60 W (including PSU losses, without regen dissipation)
Weight
Approximately 2.7 kg
Width And Depth
70 mm wide; 171 mm deep (without connectors)
Instructions

Use this calculator to convert between different units of mass. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Mass

Mass is a fundamental property of objects that measures the amount of matter contained within. It is distinct from weight, which depends on both mass and the gravitational force acting on it. The International System of Units (SI) uses the kilogram (kg) as the standard unit of mass. Familiarity with mass and its units is crucial in various fields, including physics, engineering, and industrial automation.

Importance for Industrial Automation and Servomotors

In industrial automation, precise control of mass and weight is paramount. For instance, servomotors, which are integral components in automation, rely on accurate mass calculations to optimize performance and efficiency. These motors use feedback systems to ensure precise movement, which requires accounting for the mass of mechanical parts and loads. By effectively managing mass, automation systems can achieve higher precision and reliability, minimizing energy consumption and wear on components.

Understanding and converting mass units can enhance the adaptability of automation systems in a global market, where different countries and industries may use diverse measurement units. Thus, a mass conversion tool serves as a practical resource for engineers and technicians, facilitating seamless integration and operation across different scales and measurement standards.

Instructions

Use this calculator to convert between different units of mass. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Mass

Mass is a fundamental property of objects that measures the amount of matter contained within. It is distinct from weight, which depends on both mass and the gravitational force acting on it. The International System of Units (SI) uses the kilogram (kg) as the standard unit of mass. Familiarity with mass and its units is crucial in various fields, including physics, engineering, and industrial automation.

Importance for Industrial Automation and Servomotors

In industrial automation, precise control of mass and weight is paramount. For instance, servomotors, which are integral components in automation, rely on accurate mass calculations to optimize performance and efficiency. These motors use feedback systems to ensure precise movement, which requires accounting for the mass of mechanical parts and loads. By effectively managing mass, automation systems can achieve higher precision and reliability, minimizing energy consumption and wear on components.

Understanding and converting mass units can enhance the adaptability of automation systems in a global market, where different countries and industries may use diverse measurement units. Thus, a mass conversion tool serves as a practical resource for engineers and technicians, facilitating seamless integration and operation across different scales and measurement standards.

Instructions

How to Determine What Torque You Need for Your Servo Motors

When building a robotic system with servo motors, determining the appropriate torque for each motor is essential. Torque is what allows the servo motor to effectively lift, hold, or move an object. Without sufficient torque, your motor either won’t perform as expected or may damage itself trying.

Here, we’ll break down how to calculate the torque you need, then pivot into some key nuances around how torque works in different contexts.

What Is Torque?

Illustration of torque around a central axis

Torque is a force applied over a distance that causes rotation. You use torque every day when you twist open a jar or turn a doorknob. In the case of servo motors—specifically in robotics—torque determines how much weight a motor can rotate at a certain distance away from its axis. Think about a robotic arm lifting a heavy object: the motor's torque directly affects how much weight the arm can lift, and at what speed.

Mathematically, torque is expressed as:

τ = r × F

  • τ is torque,
  • r is the distance from the axis of rotation,
  • F is the force applied.

If that feels abstract, consider that F is usually the force caused by gravity, meaning it depends on the weight of the object and its distance from the motor's center.

Torque and Servo Motors: The Core Relationship

Illustration of a load at the end of a lever demonstrating it

Servo motors are frequently used in robotic arms or other machines with rotational mechanisms. The amount of torque a servo motor can exert determines its capability to perform mechanical tasks, especially when dealing with varying loads.

The lever arm length—the distance from the rotation point to the load—amplifies the effect of the weight being moved. A longer lever arm requires more torque even if the weight remains the same. So, as we dive into calculations, remember that torque isn't just about force; it’s also about how far away from the motor's axis that force is applied.

Formula Recap

The standard torque equation for servo motors typically used in applications like robotic arms can be expanded slightly:

τ = r × m × g

  • r is the distance from the motor's axis to where the load is applied,
  • m is the mass of the item being moved (in kilograms),
  • g is the acceleration of gravity (~9.81 m/s²).

Let’s translate this into something more immediately practical: a robotic arm needs torque to lift an object at the end of the arm. If the arm is long, you’ll need more torque to achieve that same lift, even if the object you’re lifting doesn’t change in weight.

Components of Torque in Servo Motors

1. Weight of Components

The force caused by the weight of objects being moved is simple physics. Every load you expect the motor to handle has a weight. Multiplied by gravity, that’s your F.

A robotic arm lifting a box must overcome the weight of the box. However, the motor also needs to account for the weight of the components themselves, like robotic arm links or grippers.

2. Distance from the Pivot

The lever arm length is just as crucial. Calculating torque by only considering force and weight without factoring in the arm’s length will result in inaccurate torque requirements and potentially a poor design.

Case Study: A Simple Robotic Arm

Imagine an arm that needs to lift a 1.5 kg box at the end of a 0.5-meter-long arm.

  • m = 1.5 kg
  • r = 0.5 m
  • g = 9.81 m/s² (constant)

We’re now ready to plug in values:

τ = r × m × g

τ = 0.5 m × 1.5 kg × 9.81 m/s²

τ = 7.36 Nm

This means you require a minimum torque of 7.36 Newton-meters (Nm) to lift the box at the end of this particular robotic arm.

Angular Acceleration

In any instance where you need the servo motor to move a load and not just hold it, you must also account for angular acceleration. Angular acceleration means your motor needs extra torque at the beginning and during changes in movement. To calculate it:

τ = I × α

  • I is the moment of inertia of the robot arm (resistance to angular motion),
  • α is angular acceleration.

This means that for movements such as high-speed rotations or rapid direction changes, torque requirements jump. The speed with which the load moves and how quickly the direction changes are factored into torque calculations for dynamic motion.

Final Thoughts

To summarize everything, calculating torque isn’t just as simple as deciding how heavy a load is. It requires you to think about:

  • Distance (where the weight is applied from the axis),
  • Weight of the object being moved,
  • The weight of other mechanical components (like links and joints inside the machine),
  • Angular acceleration, especially if the motor will be moving or changing directions rapidly,
  • Safety margins (plan a buffer of 20-30% torque capability beyond the minimum).

The general idea is that the larger the load or the further away from the pivot, the more torque you need. By thinking through all of these details, you can properly size your servo motor torque needs, ensuring your motor will handle everything smoothly without underperformance during operation.

Get expert servo motor guidance and competitive pricing from Wake Industrial. Whether you need one motor or a complete system, we'll help you find the right solution at the right price. Call 1-919-443-0207 now for a quick quote or email sales@wakeindustrial.com to browse our extensive servo motor inventory.

Instructions

How to Determine What Torque You Need for Your Servo Motors

When building a robotic system with servo motors, determining the appropriate torque for each motor is essential. Torque is what allows the servo motor to effectively lift, hold, or move an object. Without sufficient torque, your motor either won’t perform as expected or may damage itself trying.

Here, we’ll break down how to calculate the torque you need, then pivot into some key nuances around how torque works in different contexts.

What Is Torque?

Illustration of torque around a central axis

Torque is a force applied over a distance that causes rotation. You use torque every day when you twist open a jar or turn a doorknob. In the case of servo motors—specifically in robotics—torque determines how much weight a motor can rotate at a certain distance away from its axis. Think about a robotic arm lifting a heavy object: the motor's torque directly affects how much weight the arm can lift, and at what speed.

Mathematically, torque is expressed as:

τ = r × F

  • τ is torque,
  • r is the distance from the axis of rotation,
  • F is the force applied.

If that feels abstract, consider that F is usually the force caused by gravity, meaning it depends on the weight of the object and its distance from the motor's center.

Torque and Servo Motors: The Core Relationship

Illustration of a load at the end of a lever demonstrating it

Servo motors are frequently used in robotic arms or other machines with rotational mechanisms. The amount of torque a servo motor can exert determines its capability to perform mechanical tasks, especially when dealing with varying loads.

The lever arm length—the distance from the rotation point to the load—amplifies the effect of the weight being moved. A longer lever arm requires more torque even if the weight remains the same. So, as we dive into calculations, remember that torque isn't just about force; it’s also about how far away from the motor's axis that force is applied.

Formula Recap

The standard torque equation for servo motors typically used in applications like robotic arms can be expanded slightly:

τ = r × m × g

  • r is the distance from the motor's axis to where the load is applied,
  • m is the mass of the item being moved (in kilograms),
  • g is the acceleration of gravity (~9.81 m/s²).

Let’s translate this into something more immediately practical: a robotic arm needs torque to lift an object at the end of the arm. If the arm is long, you’ll need more torque to achieve that same lift, even if the object you’re lifting doesn’t change in weight.

Components of Torque in Servo Motors

1. Weight of Components

The force caused by the weight of objects being moved is simple physics. Every load you expect the motor to handle has a weight. Multiplied by gravity, that’s your F.

A robotic arm lifting a box must overcome the weight of the box. However, the motor also needs to account for the weight of the components themselves, like robotic arm links or grippers.

2. Distance from the Pivot

The lever arm length is just as crucial. Calculating torque by only considering force and weight without factoring in the arm’s length will result in inaccurate torque requirements and potentially a poor design.

Case Study: A Simple Robotic Arm

Imagine an arm that needs to lift a 1.5 kg box at the end of a 0.5-meter-long arm.

  • m = 1.5 kg
  • r = 0.5 m
  • g = 9.81 m/s² (constant)

We’re now ready to plug in values:

τ = r × m × g

τ = 0.5 m × 1.5 kg × 9.81 m/s²

τ = 7.36 Nm

This means you require a minimum torque of 7.36 Newton-meters (Nm) to lift the box at the end of this particular robotic arm.

Angular Acceleration

In any instance where you need the servo motor to move a load and not just hold it, you must also account for angular acceleration. Angular acceleration means your motor needs extra torque at the beginning and during changes in movement. To calculate it:

τ = I × α

  • I is the moment of inertia of the robot arm (resistance to angular motion),
  • α is angular acceleration.

This means that for movements such as high-speed rotations or rapid direction changes, torque requirements jump. The speed with which the load moves and how quickly the direction changes are factored into torque calculations for dynamic motion.

Final Thoughts

To summarize everything, calculating torque isn’t just as simple as deciding how heavy a load is. It requires you to think about:

  • Distance (where the weight is applied from the axis),
  • Weight of the object being moved,
  • The weight of other mechanical components (like links and joints inside the machine),
  • Angular acceleration, especially if the motor will be moving or changing directions rapidly,
  • Safety margins (plan a buffer of 20-30% torque capability beyond the minimum).

The general idea is that the larger the load or the further away from the pivot, the more torque you need. By thinking through all of these details, you can properly size your servo motor torque needs, ensuring your motor will handle everything smoothly without underperformance during operation.

Get expert servo motor guidance and competitive pricing from Wake Industrial. Whether you need one motor or a complete system, we'll help you find the right solution at the right price. Call 1-919-443-0207 now for a quick quote or email sales@wakeindustrial.com to browse our extensive servo motor inventory.

Instructions

Use this calculator to convert between different units of power. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Power Units

Power is a foundational concept in both everyday life and industrial applications. The term "watts" is ubiquitous, named after James Watt, a pivotal figure in the industrial revolution known for his advancements in steam engine technology. A watt represents the rate at which energy is transferred or converted and forms the basis for other power units such as kilowatts (1,000 watts), megawatts (1,000,000 watts), and more.

Importance in Industrial Automation and Servomotors

In industrial automation, precise power control is critical for maximizing efficiency and accuracy. Servomotors, essential components in automation systems, rely heavily on accurate power measurement. These motors, often used in robotics and CNC machinery, require specific power inputs to function correctly, translating electrical energy into controlled movements. The ability to convert between different power units helps engineers and technicians optimize these systems for energy consumption and performance. Whether ensuring that a robotic arm operates with sufficient power or managing the electrical requirements of a complex assembly line, understanding and converting power units is a crucial skill.

As technology advances, the necessity for precision grows. Power conversion tools, therefore, play an indispensable role in maintaining system efficiency and reliability, making them a staple in the toolkit of modern engineers and industrial technicians.

Instructions

Use this calculator to convert between different units of power. Select the units you want to convert from and to, enter the value, and click "Convert" to see the result.

Understanding Power Units

Power is a foundational concept in both everyday life and industrial applications. The term "watts" is ubiquitous, named after James Watt, a pivotal figure in the industrial revolution known for his advancements in steam engine technology. A watt represents the rate at which energy is transferred or converted and forms the basis for other power units such as kilowatts (1,000 watts), megawatts (1,000,000 watts), and more.

Importance in Industrial Automation and Servomotors

In industrial automation, precise power control is critical for maximizing efficiency and accuracy. Servomotors, essential components in automation systems, rely heavily on accurate power measurement. These motors, often used in robotics and CNC machinery, require specific power inputs to function correctly, translating electrical energy into controlled movements. The ability to convert between different power units helps engineers and technicians optimize these systems for energy consumption and performance. Whether ensuring that a robotic arm operates with sufficient power or managing the electrical requirements of a complex assembly line, understanding and converting power units is a crucial skill.

As technology advances, the necessity for precision grows. Power conversion tools, therefore, play an indispensable role in maintaining system efficiency and reliability, making them a staple in the toolkit of modern engineers and industrial technicians.

Frequently Asked Questions about SERVOSTAR-343:

Q: What advantage does the rated output current specification offer in SERVOSTAR-343?

A: It delivers 5 Arms at lower voltages, adapting to different power levels. It enables precise control across various motor applications.

Q: What benefit does the 2.5 kVA rated input power provide in SERVOSTAR-343 drive?

A: The drive supports steady performance under standard load conditions and ensures efficient operation during S1 operation.

Q: What role does the switching frequency play in SERVOSTAR-343 device?

A: The 8 kHz (16 kHz at 50% load) frequency improves the drive’s dynamic response and control precision to support rapid adjustments in operation.

Q: What benefit do the motor inductance minimum values provide to this module?

A: It ensures stable operation with low-inductance motors, optimizing the drive’s performance across different motor types.

Q: What is the advantage of the built-in diagnostic LED display in the drive?

A: The SERVOSTAR-343’s LED provides immediate error code feedback for troubleshooting. It simplifies maintenance and reduces downtime.


Internal Product Review

  • ‘‘SERVOSTAR-343’s rated input power of 2.5 kVA delivers consistent energy management for your drive systems. This power specification guarantees reliable performance in practical applications, ensuring efficient load handling during normal operation.’’

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